Question

10x+6y=4 5x+3y=2 método igualación

Answer 1

RESOLVER:

$\left \{ {{10x+6y=4} \atop {5x+3y=2}} \right.$

$10x+6y=4\\\\10x=4-6y\\\\x=\frac{4}{10}-\frac{6y}{10}\\\\x=\frac{4-6y}{10}\\\\x=\frac{2\left(2-3y\right)}{10}\\\\x=\frac{2-3y}{5}$

Sustituimos $x=\frac{2-3y}{5}$

$\left \{ {{5\cdot \frac{2-3y}{5}+3y=2}}} \right.$

$5\cdot \frac{2-3y}{5}\\\\=\frac{\left(2-3y\right)\cdot \:5}{5}\\\\=2-3y\\\\2-3y+3y=2\\\\-3y+3y=0\\\\2=2\\\\\boxed{x=\frac{2-3y}{5}}$

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