Question

100- (7+3(10-15)+7(130-140)5
$-100 -{7 + 3(10 - 15) + 7(130 - 140)5 }^{2}$


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Answer 1

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100- (7+3(10-15)+7(130-140)5^2

=100−(7+(3)(−5)+7(130−140)(5^2))

=100−(7+−15+7(130−140)(5^2))

=100−(−8+7(130−140)(5^2))

=100−(−8+(7)(−10)(5^2))

=100−(−8+−70(5^2))

=100−(−8+(−70)(25))

=100−(−8+−1750)

=100−(−1758)

=1858