Question

10. Hallar : Tgπ
+ cos2 π+sen31 π​

Answer 1

Hola :3

CGF=π

π=( tgπ/π +cos(2)π/π + sen(31)π/π )=

π=( tg+cos(2)+sen(31) )

Done ✓

By: Alik

Answer 2

$\equiv\fbox\red{{Matematica}}\ \equiv$

【Rpta.】πTg + πcos ( 2 )

${\hspace{50 pt}\above 1.2 pt}\boldsymbol{\mathsf{Procedimiento}}{\hspace{50 pt}\above 1.2 pt}$

sin ( 31π ) = 0

π Tg + π cos (2) + 0

Tgπ + cos (2) π + 0 = Tgπ + cos (2) π

πTg + πcos (2)

Saludos ✌