Question

10. Calcula el resultado de (Q + 12) + (R: 5), si
Q = √225 + 3² - 16÷4
R = 121° + 8²-√32 x 50
a. 40
C. 20
b. 37
d. 25​

Answer 1

Respuesta:

$Q = \sqrt{225} + {3}^{2} - 16 \div 4 \\ Q = 15 + 9 - 4 \\ Q = 20$

$R = {121}^{0} + {8}^{2} - \sqrt{32 \times 50} \\ R = 1 + 64 - \sqrt{1600} \\ R = 1 + 64 - 40 \\ R = 25$

$(Q + 12) + (R: 5) = \\ (20 + 12) + (25 \div 5) = \\ 32 + 5 = \\ 37$