Question

10÷-(-2)+18(-3)+{-18×2+[8÷2-1×(-4)]+45÷(-15)}-12÷-4
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Answer 1

Respuesta:

15

Explicación paso a paso:

$\tt10 \div -( - 2) + 18( - 3) + \{ - 18 \times 2 + [8 \div 2 - 1 \times ( - 4)] + 45 \div ( - 15) \} - 12 \div - 4 \\ = \tt10 \div - ( - 2) + 18 ( - 3) + \{ - 18 \times 2 + [8 \div 2 - ( - 4)] + 45 \div ( - 15) \} - 12 \div - 4 \\ = \tt10 \div - ( - 2) + 18( - 3) + \{ - 18 \times 2 + [4 - ( - 4)] + 45 \div ( - 15) \} - 12 \div - 4 \\ = \tt10 \div - ( - 2) + 18( - 3) + \{ - 18 \times 2 +[8] + 45 \div ( - 15) \} - 12 \div - 4 \\ \tt = 10 \div - ( - 2) + 18( - 3) + \{36 + 8 + 45 \div ( - 15) \} - 12 \div - 4 \\ \tt = 10 \div - ( - 2) + 18( - 3) + \{36 + 8 + ( - 3) \} - 12 \div - 4 \\ \tt = 10 \div - ( - 2) + 18( - 3) + \{ 41\} - 12 \div - 4 \\ \tt = 10 \div ( - 2) + ( - 54) + 41 - 12 \div - 4 \\ \tt = ( - 5) + ( - 54) + 41 - ( - 3) \\ \tt = 18 - ( - 3) \\ \underline{ \boxed{\orange{\tt \: = 15 \: \: }}}$