Matemáticas, pregunta formulada por alexandreromeroharo, hace 1 año

1. (x - y) (x + y) = x2 + y2 (V) (F) 2. (2x - 3) (2x + 4) = 4x2 + x + 12 (V) (F) 3. (yx - 1) (yx + 3) = y2x 2 + 2yx – 3 (V) (F) 4. (3x2 + y) (3x2 - y) = 9x4 – y 2 (V) (F) 5. ( 5 y - 2) ( 5 y + 5) = 5y + 3 5 y – 10 (V) (F) 6. (x - 2) (x + 3) = x2 – x – 6 (V) (F) 7. (y + 1) (y - 2) = y2 – y + 2 (V) (F) 8. (2y + 3) (2y - 1) = 4y2 + 4y – 3 (V) (F) 9. (3x3 - 1) (3x3 + 2) = 9x6 + 3x3 – 2 (V) (F) con desarrollo AYUDAAAAAAAAA

Respuestas a la pregunta

Contestado por SHARLOTH17
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Respuesta:

Explicación paso a paso:

1. (x - y) (x + y) = x2 + y2 (V) (F)

=(x+−y)(x+y)

=(x)(x)+(x)(y)+(−y)(x)+(−y)(y)

=x2+xy−xy−y2

=x2−y2

2. (2x - 3) (2x + 4) = 4x2 + x + 12 (V) (F)

=(2x+−3)(2x+4)

=(2x)(2x)+(2x)(4)+(−3)(2x)+(−3)(4)

=4x2+8x−6x−12

=4x2+2x−12

3. (yx - 1) (yx + 3) = y2x 2 + 2yx – 3 (V) (F)

=(yx+−1)(yx+3)

=(yx)(yx)+(yx)(3)+(−1)(yx)+(−1)(3)

=x2y2+3xy−xy−3

=x2y2+2xy−3

4. (3x2 + y) (3x2 - y) = 9x4 – y 2 (V) (F)

=(3x2+y)(3x2+−y)

=(3x2)(3x2)+(3x2)(−y)+(y)(3x2)+(y)(−y)

=9x4−3x2y+3x2y−y2

=9x4−y2

5. ( 5 y - 2) ( 5 y + 5) = 5y + 3 5 y – 10 (V) (F)

=(5y+−2)(5y+5)

=(5y)(5y)+(5y)(5)+(−2)(5y)+(−2)(5)

=25y2+25y−10y−10

=25y2+15y−10

6. (x - 2) (x + 3) = x2 – x – 6 (V) (F)

=(x+−2)(x+3)

=(x)(x)+(x)(3)+(−2)(x)+(−2)(3)

=x2+3x−2x−6

=x2+x−6

7. (y + 1) (y - 2) = y2 – y + 2 (V) (F)

=(y+1)(y+−2)

=(y)(y)+(y)(−2)+(1)(y)+(1)(−2)

=y2−2y+y−2

=y2−y−2

8. (2y + 3) (2y - 1) = 4y2 + 4y – 3 (V) (F)

=(2y+3)(2y+−1)

=(2y)(2y)+(2y)(−1)+(3)(2y)+(3)(−1)

=4y2−2y+6y−3

=4y2+4y−3

9. (3x3 - 1) (3x3 + 2) = 9x6 + 3x3 – 2 (V) (F)

=(3x3+−1)(3x3+2)

=(3x3)(3x3)+(3x3)(2)+(−1)(3x3)+(−1)(2)

=9x6+6x3−3x3−2

=9x6+3x3−2

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