Question

1) x - 3 = 3 - x
2) 2(3x - 2) = 2
3) 3x + 1 = 3 - (2 - 2x)
4) - 2(3x - 2) = -2
5) 2x - 1 = 5x + 8
Nesecito con procedimiento gracias

Answer 1

Respuesta:

Hola.

Bien ahí vamos ♦

1)

$x - 3 = 3 - x$

$x + x = 3 + 3$

$2x = 6$

$\frac{2x}{2} = \frac{6}{2}$

$x = 3$

Comprobamos !

$3 - 3 = 3 - 3$

$0 = 0$

2)

$2(3x - 2) = 2$

$6x - 4 = 2$

$6x = 2 + 4$

$6x = 6$

$\frac{6x}{6} = \frac{6}{6}$

$x = 1$

Comprobamos !

$2(3.1 - 2) = 2$

$2(3 - 2) = 2$

$2(1) = 2$

$2 = 2$

3)

$3x + 1 = 3 - (2 - 2x)$

$3x + 1 = 3 - 2 + 2x$

$3x + 1 = 1 + 2x$

$3x - 2x = 1 - 1$

$x = 0$

Comprobamos !

$3(0) + 1 = 3 - (2 - 2(0))$

$0 + 1 = 3 - 2 - 0$

$1 = 1$

4)

$- 2( 3x - 2) = - 2$

$- 6x + 4 = - 2$

$- 6x = - 2 - 4$

$- 6x = - 6$

Multiplicamos ambos lados por (-1)

$6x = 6$

$\frac{6x}{6} = \frac{6}{6}$

$x = 1$

Comprobamos !

$- 2(3(1) - 2) = - 2$

$- 2(3 - 2) = - 2$

$- 2(1) = - 2$

$- 2 = - 2$

5)

$2x - 1 = 5x + 8$

$2x - 5x = 8 + 1$

$- 3x = 9$

$\frac{ - 3x}{ - 3} = \frac{9}{ - 3}$

$x = - 3$

Comprobamos !

$2( - 3) - 1 = 5( - 3) + 8$

$- 6 - 1 = - 15 + 8$

$- 7 = - 7$

Saludos