Question

1) x + 2x + 3x = 1+2+3
2) 3x -1 = x +2 + x
3) (x – 3) (x + 2) – (x + 5) (x – 1) = 3x
4) 4x – (2x – 1) + x = 2x – (2 + x) -x
5) 5x + (2x + 3) =7x – (5 – x)
6) X3 - [(+1)+3]=1−2
7) 7x - [(+5)−(3−1)]=12
8) 3x(+1)=2+(5+3)
9) (−5)2−(+2)=1
POR FAVOR AYUNDEME DOY CORONITA :)

Answer 1

Respuesta:

Explicación paso a paso:

1) x + 2x + 3x = 1+2+3

  6x = 6 => x = 1

2) 3x - 1 = x +2 + x

   3x - 2x = 2 + 1 => x = 3

3) (x – 3) (x + 2) – (x + 5) (x – 1) = 3x

   x2 + 2x - 3x - 6 - (x2 - x + 5x - 5) = 3x

   x2 + 2x - 3x - 6 - x2 + x - 5x + 5 = 3x

   -5x - 1 = 3x => -1 = 8x => x = -1/8

4) 4x – (2x – 1) + x = 2x – (2 + x) -x

   4x - 2x + 1 + x = 2x - 2 - x - x

   3x + 1 = -2

   3x = -3 => x = -1

5) 5x + (2x + 3) =7x – (5 – x)

   5x + 2x + 3 = 7x - 5 + x

   7x + 3 = 8x - 5

   8 = x

6) X3 - [(+1)+3]=1−2

   x3 - 3 = -1 => x3 = 2 => $\sqrt[3]{2}$

7) 7x - [(+5)−(3−1)]=12

   7x - 3 = 12

   7x = 15 => x = 15/7

8) 3x(+1)=2+(5+3)

   3x = 9 => x = 3

9) (−5)2−(+2)=1

   25 - 2 = 1 => 23 = 1 ?¡?¡?¡?¡?¡