1) x(2x 3) 3(5 x) = 83
2) (2x + 5)(2x 5) = 11
3) (7 + x)2 + (7 x)2 = 130
4) (2x 3)(3x 4) (x 13)(x 4) = 40
5) (3x 4)(4x 3) (2x 7)(3x 2) = 214
8(2 x)2 = 2(8 x)2
ayudenemen ahy que determinar las raices de ecuaciones cuadratizas gracias
Respuestas a la pregunta
1.- x(2x 3) 3(5 x) = 83
2x²-3x-15+3x=83
2x²-98=0
x²-49=0
(x+7)(x-7)=0
x=7
x=-7
2.- (2x + 5)(2x 5) = 11
4x²-25=11
4x²-36=0
(2x-6)(2x+6)=0 igualando a o y despejando x
x=3
x=-3
3.- (7 + x)² + (7 x)² = 130 supongo que es asi
49+14x+x²+49-14x+x²=130
2x²-32=0
x²-16=0
(x-4)(x+4)=0
x=4
x=-4
4.-(2x 3)(3x 4) (x 13)(x 4) = 40
6x²-17x+12-(x²-17x+52)=40
6x²-17x+12-x²+17x-52-40=0
5x²-80=0
x²-16=0
(x-4)(x+4)=0
x=4
x=-4
5.-(3x 4)(4x 3) (2x 7)(3x 2) = 214
12x²-25x+12-(6x²-25x+14)=214
12x²-25x+12-6x²+25x-14-214=0
6x²-216=0
x²-36=0
(x-6)(x+6)=0
x=6
x=-6
8.- (2 x)² = 2(8 x)² supong que es asi
4-4x+x²=2(64-16x+x²)
4-4x+x²=128-32x+2x²
x²-28x-124=0 aplicando la formula
x=31.88
x=-3.8888
espero te sirva, saludos
1) x(2x 3) 3(5 x) = 83
2x^2 -3x -15 +3x=83
2x^2-15-83=0
2x^2 -98= 0
x^2 -49=0
(x+7)(x-7)
x=-7 y x=7
2) (2x + 5)(2x 5) = 11
4x^2 -25=11
4x^2 -25 -11=0
4x^2 -36=0
x^2 -9=0
(x-3)(x+3)=0
x=3 y x=-3
3) (7 + x)2 + (7 x)2 = 130
49 +14x +x^2 + 49 -14x +x^2=130
98 +2x^2=130
2x^2 - 32=0
x^2 -16=0
(x-4)(x+4)=0
x=4 y x=-4
4) (2x 3)(3x 4) (x 13)(x 4) = 40
6x^2 -8x -9x +12 -(x^2 -17x + 52)=40
6x^2-17x +12 -x^2 +17x -52=40
5x^2 -40=40
5x^2 -80=0
x^2 -16=0
(x+4)(x-4)=0
x=-4 y x=4
5) (3x 4)(4x 3) (2x 7)(3x 2) = 214
12x^2 -9x -16x +12 -(6x^2 -4x -21x +14)=214
12x^2 -25x +12 -6x^2 +25x -14=214
6x^2 -2=214
6x^2 -216=0
x^2 -36=0
(x+6)(x-6)=0
x=-6 y x=6
6) 8(2 x)2 = 2(8 x)2
8(4-4x+x^2)= 2(64 -16x +x^2)
32-32x+ 8x^2 = 128 -32x +2x^2
6x^2 -96=0
x^2 - 16=0
(x+4)(x-4) =0
x=-4 y x=4