1)supriman previamente los parentesis y luego resuelvan
a) 9-(+6)= c) -(-3+11)-(8+9)= d) -(+7)+(-3)= e) +(-4+9)-(+6)=
b) -(-2)-(-8)= f) (-1+4)-(17-6)= g) +(-5)-(-5)= h) -(-10)+(+3-15)=
i) -(-8+3)+(17-6)=
2)resuelvan las siguientes sumas algebraicas
a) 7-8+4-10+6-5-9= b) -12+7-6-10+3+4+2= c)8+9-13-17+21-16-2=
Respuestas a la pregunta
Respuesta:
1)
a) 9 – (+6) = 9 – 6 = 3
b) – (–2) – (–8) = 2 + 8 = 10
c) – (–3 + 11) – (8 + 9) = – (+8) – (+17) = –8 – 17 = –25
d) – (+7) + (–3) = –7 – 3 = –10
e) + (–4 + 9) – (+6) = + (+5) – (+6) = 5 – 6 = –1
f) (–1 + 4) – (17 – 6) = (+3) – (+11) = 3 – 11 = –8
g) + (–5) – (–5) = –5 + 5 = 0
h) – (–10) + (+3 – 15) = – (–10) + (–12) = 10 – 12 = –2
i) – (–8 + 3) + (17 – 6) = – (–5) + (+11) = 5 + 11 = 16
2)
a) 7 – 8 + 4 – 10 + 6 – 5 – 9 = (7 + 4 + 6) – (8 + 10 + 5 + 9) = 17 – 32 = –15
b) –12 + 7 – 6 – 10 + 3 + 4 + 2 = (7 + 3 + 4 + 2) – (12 + 6 + 10) = 16 – 28 = –12
c) 8 + 9 – 13 – 17 + 21 – 16 – 2 = (8 + 9 + 21) – (13 + 17 + 16 + 2) = 38 – 48 = –10
Respuesta:
1)
a) 9 – (+6) = 9 – 6 = 3
b) – (–2) – (–8) = 2 + 8 = 10
c) – (–3 + 11) – (8 + 9) = – (+8) – (+17) = –8 – 17 = –25
d) – (+7) + (–3) = –7 – 3 = –10
e) + (–4 + 9) – (+6) = + (+5) – (+6) = 5 – 6 = –1
f) (–1 + 4) – (17 – 6) = (+3) – (+11) = 3 – 11 = –8
g) + (–5) – (–5) = –5 + 5 = 0
h) – (–10) + (+3 – 15) = – (–10) + (–12) = 10 – 12 = –2
i) – (–8 + 3) + (17 – 6) = – (–5) + (+11) = 5 + 11 = 16
2)
a) 7 – 8 + 4 – 10 + 6 – 5 – 9 = (7 + 4 + 6) – (8 + 10 + 5 + 9) = 17 – 32 = –15
b) –12 + 7 – 6 – 10 + 3 + 4 + 2 = (7 + 3 + 4 + 2) – (12 + 6 + 10) = 16 – 28 = –12
c) 8 + 9 – 13 – 17 + 21 – 16 – 2 = (8 + 9 + 21) – (13 + 17 + 16 + 2) = 38 – 48 = –10
Explicación paso a paso: