Question

1. Resolver las sumas y restas:

Answer 1

Respuesta:

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$1.\frac{3x + 4}{x + 1} 2.\frac{2x^{2}- 4x-5 }{x^{2} -1} 3.\frac{5x^{2} -3x+6}{x^{3}+x^{2} }$

Answer 2

Respuesta:

1.

$\frac{2x-2}{x^2-1}+\frac{3x^2-1}{x^2-1}-\frac{x+1}{x^2-1}\\\\=\frac{2x-2+3x^2-1-\left(x+1\right)}{x^2-1}\\\\=\frac{3x^2+x-4}{x^2-1}\\\\=\frac{\left(x-1\right)\left(3x+4\right)}{x^2-1}\\\\=\frac{\left(x-1\right)\left(3x+4\right)}{x^2-1}\\\\=\frac{3x+4}{x+1}$

2.

$\frac{3x}{x^2-1}+\frac{2x}{x+1}-\frac{5}{x-1}\\\\=\frac{3x}{\left(x+1\right)\left(x-1\right)}+\frac{2x}{x+1}-\frac{5}{x-1}\\\\=\frac{3x}{\left(x+1\right)\left(x-1\right)}+\frac{2x\left(x-1\right)}{\left(x+1\right)\left(x-1\right)}-\frac{5\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}\\\\=\frac{3x+2x\left(x-1\right)-5\left(x+1\right)}{\left(x+1\right)\left(x-1\right)}\\\\=\frac{2x^2-4x-5}{\left(x+1\right)\left(x-1\right)}$

3.

$\frac{2}{x}+\frac{3}{x+1}-\frac{5x-6}{x^3+x^2}\\\\=\frac{2}{x}+\frac{3}{x+1}-\frac{5x-6}{x^2\left(x+1\right)}\\\\=\frac{2x\left(x+1\right)}{x^2\left(x+1\right)}+\frac{3x^2}{\left(x+1\right)x^2}-\frac{5x-6}{x^2\left(x+1\right)}\\\\=\frac{2x\left(x+1\right)+3x^2-\left(5x-6\right)}{x^2\left(x+1\right)}\\\\=\frac{5x^2-3x+6}{x^2\left(x+1\right)}$