Question

1. Halla los ceros de las funciones cuadráticas mostradas, por factoreo:
a. 4x^2+4x+1=0
b. x^2+5x=0
c. 3x^2+11x-4=0
d. x^2+2x=40-x
e) 3x^2−9x−20=x^2+5x+16
ALGUIEN QUE ME AYUDE , LO NECESITO PARA HOY

Answer 1

a. 4x² + 4x + 1 = 0

(2x + 1)² = 0

2x + 1 = 0

2x = -1

$\pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{x = - \frac{1}{2} }}{\hspace{0pt}\above 2.2pt}}$

b. x² + 5x = 0

x (x + 5) = 0

x = 0

x + 5 = 0

$\pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{x = 0}}{\hspace{0pt}\above 2.2pt}}$

$\pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{x = - 5}}{\hspace{0pt}\above 2.2pt}}$

c. 3x² + 11x -4 = 0

3x² + 12x - x - 4 = 0

3x (x + 4) - (x+4) = 0

(x + 4) (3x - 1) = 0

x + 4 = 0

3x - 1 = 0

$\pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{x = - 4}}{\hspace{0pt}\above 2.2pt}}$

$\pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{x = \frac{1}{3} }}{\hspace{0pt}\above 2.2pt}}$

d. x² + 2x = 40 - x

x² + 2x - 40 + x = 0

x² + 3x - 40 = 0

x² + 8x - 5x - 40 = 0

x (x+8) - 5 (x+8) = 0

(x+8) (x-5) = 0

x + 8 = 0

x - 5 = 0

$\pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{x = - 8}}{\hspace{0pt}\above 2.2pt}}$

$\pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{x = 5}}{\hspace{0pt}\above 2.2pt}}$

_____________________________