Question

1.- Evalué la función en los siguientes valores:

a) f (1)=

b) f(X+1)=

c) f(-2)=

d) f(0) =


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Answer 1

Para poder evaluar un valor en una función solo necesitamos reemplazar

                                                  $\boxed{\sf{f(x)=2x^2-3x+3}}$

a) f(1) =

                                               $\begin{array}{c}\\\sf{f(x)=2x^2-3x+3}\\\\\sf{f(\boldsymbol{\sf{1}})=2(\boldsymbol{\sf{1}})^2-3(\boldsymbol{\sf{1}})+3}\\\\\sf{f(1)=2(1)-3+3}\\\\\boxed{\boxed{\boldsymbol{\blue{\sf{f(1)=2}}}}}\end{array}$

b) f(x+1) =

                                    $\begin{array}{c}\\\sf{f(x)=2x^2-3x+3}\\\\\sf{f(\boldsymbol{\sf{x+1}})=2(\boldsymbol{\sf{x+1}})^2-3(\boldsymbol{\sf{x+1}})+3}\\\\\sf{f(x+1)=2(x^2+2x+1)-3x-3+3}\\\\\boxed{\boxed{\boldsymbol{\blue{\sf{f(x+1)=2x^2+x+2}}}}}\end{array}$

c) f(-2) =

                                          $\begin{array}{c}\\\sf{f(x)=2x^2-3x+3}\\\\\sf{f(\boldsymbol{\sf{-2}})=2(\boldsymbol{\sf{-2}})^2-3(\boldsymbol{\sf{-2}})+3}\\\\\sf{f(-2)=2(4)+6+3}\\\\\boxed{\boxed{\boldsymbol{\blue{\sf{f(-2)=17}}}}}\end{array}$

d) f(0) =

                                                $\begin{array}{c}\\\sf{f(x)=2x^2-3x+3}\\\\\sf{f(\boldsymbol{\sf{0}})=2(\boldsymbol{\sf{0}})^2-3(\boldsymbol{\sf{0}})+3}\\\\\sf{f(0)=2(0)-0+3}\\\\\boxed{\boxed{\boldsymbol{\blue{\sf{f(0)=3}}}}}\end{array}$

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