Question

1.efectuar:
(-4)(-2)+(-3)(+2)-(-5)(-1)

2.hallar:
(4-5-2)(-1+2)-[(-5)(-1)-3]

3.efectuar:
op(-3)×op(+4)-op(+1)×op(-5)

4.si: A= -4+2-5+(-3)(-2)
y B= -1+(-5)(+2)
hallar: A×B

5.reducir:
(-50+10)÷(+7-15)
_____________
(-20)÷(-4)

Answer 1

(
Efectuar
(-4)(-2)+(-3)(+2)-(-5)(-1)=
8 -6 -5=
8 - 11=
-3


2.hallar:
(4-5-2)(-1+2)-[(-5)(-1)-3]=
(4-7)(1)-[5-3]=
(-3)(1) -(2)
-3 -2= 
-5

3.efectuar:
op(-3)×op(+4)-op(+1)×op(-5) ( no entiendo que es op)

4.si: A= -4+2-5+(-3)(-2)
A=-4+2-5+(-3)(-2)
A =-4+2-5+6
A=-4-5+2+6
A=-9+8
A =-1
y B= -1+(-5)(+2)
B=-1-10
B=-11
hallar: A×B
A*B =-1*-11
A*B = 11

5.reducir:
(-50+10)÷(+7-15)
_____________   =
(-20)÷(-4)

Realizando la operacion de multiplicar extremos por extremos y medios por medios:

(-50)/(-8)  /(-20)/(-4) =

(-50)(-4) / (-8)(-20) =

200/160 
simplificando
40/32=
20/16= 
10/8=
5/4