Question

1+A - 1/3 = a/6 + 1/2- 2a/9 +16

Answer 1

$1+A=-\frac{1}{3} =\frac{a}{6} +\frac{1}{2} -2*\frac{a}{9} +16\\\\\frac{2}{3} +A=\frac{a}{6} +\frac{1}{2} -\frac{2a}{9} +16\\\\\frac{2}{3} +A=-\frac{1}{18} a+\frac{33}{2} \\\\A=-\frac{1}{18} a+\frac{33}{2} -\frac{2}{3} \\\\A=-\frac{1}{18}a+\frac{95}{6}$

$A=-\frac{1}{18} a+\frac{95}{6},$ a∈R