Question

(1)/(4)+(2z-(3z-1)/(8))=(2)/(3)((z+2)/(6))-2z

Answer 1

El resultado es – 1/23.

Se pide resolver:

(1)/(4) + (2z – (3z – 1)/(8)) = (2)/(3)((z + 2)/(6)) – 2z

Resolviendo:

(1)/(4) + (2z – (3z - 1)/(8)) = (2)/(3)((z + 2)/(6)) – 2z

1/4 + (2z – 3z – 1)/8 = (2/3)[(z + 2)/6] – 2z

1/4 + (– z – 1)/8 = (2/3)[(z + 2)/6] – 2z

1/4 + (– z – 1)/8 = (2/3)[(z + 2)/6] – 2z

El Mínimo Común Múltiplo (m.c.m.) entre 4 y 8 es 8.

(2 – z – 1)/8 = (2/3)[(z + 2)/6] – 2z

(1 – z)/8 – 2z = (2/3)[(z + 2)/6]

(1 – z) – 16z/8 = (2/3)[(z + 2)/6]

(1 – 17z)/8 = (2/3)[(z + 2)/6]

3(1 – 17z)/8 = (2)[(z + 2)/6]

(3 – 51z)/8 = (2z + 4)/6

6(3 – 51z) = 8 (2z + 4)

18 – 306z = 16z + 32

18 – 32 = 16z + 306z

– 14 = 322z

Z = – 14/322

Z = – 1/23