Question

1/4+(2x-3x-1/8)=2/3(x+2/6)-2x

Answer 1

Respuesta:

$\frac{1}{4}+\left(2x-3x-\frac{1}{8}\right)=\frac{2}{3}\left(x+\frac{2}{6}\right)-2x\quad :\quad x=\frac{7}{24}\quad \left(\mathrm{Decimal}:\quad x=0.29166\dots \right)$

Explicación paso a paso:

$\frac{1}{4}+\left(2x-3x-\frac{1}{8}\right)=\frac{2}{3}\left(x+\frac{2}\\\\{6}\right)-2x\\\frac{1}{4}+2x-3x-\frac{1}{8}=\frac{2}{3}\left(x+\frac{2}{6}\right)-2x\\2x-3x+\frac{1}{4}-\frac{1}{8}=\frac{2}{3}\left(x+\frac{2}{6}\right)-2x}\\-x+\frac{1}{4}-\frac{1}{8}=\frac{2}{3}\left(x+\frac{2}{6}\right)-2x\\\frac{2}{8}-\frac{1}{8}=\frac{2}{3}\left(x+\frac{2}{6}\right)-2x\\\frac{2-1}{8}=\frac{2}{3}\left(x+\frac{2}{6}\right)-2x\\\\-x+\frac{1}{8}=\frac{2}{3}\left(x+\frac{2}{6}\right)-2x$

$-x+\frac{1}{8}=\frac{2\left(x+\frac{1}{3}\right)}{3}-2x\\-x+\frac{1}{8}-\frac{1}{8}=\frac{2\left(x+\frac{1}{3}\right)}{3}-2x-\frac{1}{8}\\-x=-\frac{1}{8}+\frac{-12x+2}{9}\\-x\cdot \:9=-\frac{1}{8}\cdot \:9+\frac{-12x+2}{9}\cdot \:9\\-x\cdot \:9=-\frac{9}{8}-12x+2\\-x\cdot \:9=-12x+\frac{7}{8}\\-x\cdot \:9+12x=-12x+\frac{7}{8}+12x\\3x=\frac{7}{8}\\\frac{3x}{3}=\frac{\frac{7}{8}}{3}\\x=\frac{7}{24}$

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