Question

(1/3)(9/5)-(9²)-1/4²​

Answer 1

RESOLVER:

$\left(\frac{1}{3}\right)\left(\frac{9}{5}\right)-\left(9^2\right)-\frac{1}{4^2}$

Quitamos los paréntesis

$=\frac{1}{3}\cdot \frac{9}{5}-9^2-\frac{1}{4^2}$

$\frac{1}{3}\cdot \frac{9}{5}=\frac{3}{5}$

$=\frac{3}{5}-9^2-\frac{1}{4^2}$

Agrupamos los términos semejantes

$=\frac{3}{5}-\frac{1}{4^2}-9^2$

$4^2=16\\\\=\frac{3}{5}-\frac{1}{16}-9^2\\\\9^2=81\\\\=\frac{3}{5}-\frac{1}{16}-81\\\\81=\frac{81}{1}\\\\=-\frac{81}{1}+\frac{3}{5}-\frac{1}{16}$

El MCM de 1, 5 y 16 es 80, entonces:

$=-\frac{6480}{80}+\frac{48}{80}-\frac{5}{80}\\\\=\frac{-6480+48-5}{80}\\\\=\frac{-6437}{80}\\\\\boxed{=-\frac{6437}{80}}$

MUCHA SUERTE...