Question

1-(2x-3)/(x+5)=(x-2)/10
procedimiento y muchas graciass

Answer 1

1-(2x-3)/(x+5)=(x-2)/10
[1(x+5)-(2x-3)]/(x+5)=(x-2)/10        comun denominador (x+5)
[x+5-2x+3]/(x+5)=(x-2)/10 
[-x+8]=(x+5)(x-2)/10
-10x+80=x²+3x-10
x²+3x-10+10x-80=0
x²+13x-90=0

x=[-13+√13²+4(90)]/2⇒x=1.54673847
o
x=[-13-√13²+4(90)]/2⇒x=-14.54673847