Question

1.- [(1/4)² x (3/5⁵) x (7/3)⁰]³ =

2.- (3/2)² x (3/2)³ =

3.- (1/100) -½ + (- 1/32)-⁵ -¹ + (-64) ⁴/³ + (1/4) -⁰,⁵=

4.- (-2/5)² x (-2/5)³=

5.- (1/2)-¹ x (1/8)-¹ x (1/4)-¹ =

6.- (-3/2)³ x (-3/2)-¹ =

7.- (1/5)-¹ x (1/9)-¹ x (1/7)-¹ x (1/4)-¹ =

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Answer 1

Respuesta:

100 d 00110 d 25 d

Explicación paso a paso:

100 25 12 18 1 18