Question

- 01- - -금) - + 1 3 Y 살​

Answer 1

Respuesta:

$\frac{1}{2} (\frac{3}{4})+(\frac{1}{2}-(\frac{1}{4}+\frac{1}{2}))=.125$
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Explicación paso a paso:

$=\frac{1}{2} (\frac{3}{4})+(\frac{1}{2}-(\frac{1}{4}+\frac{1}{2}))\\\\=\frac{1}{2} (\frac{3}{4})+(\frac{1}{2}-(\frac{1}{4}+\frac{2}{4}))\\\\=\frac{1}{2} (\frac{3}{4})+(\frac{1}{2}-(\frac{1+2}{4}}))\\\\=\frac{1}{2} (\frac{3}{4})+(\frac{1}{2}-(\frac{3}{4})\\\\=\frac{1}{2} (\frac{3}{4})+(\frac{1}{2}-\frac{3}{4}))\\\\=\frac{1}{2} (\frac{3}{4})+(\frac{2}{4}-\frac{3}{4}))\\\\=\frac{1}{2} (\frac{3}{4})+(\frac{2-3}{4})\\\\=\frac{1}{2} (\frac{3}{4})+(\frac{-1}{4})\\\\=\frac{1}{2} (\frac{3}{4})-\frac{1}{4}$

$=\frac{1*3}{2*4}-\frac{1}{4}\\\\=\frac{3}{8}-\frac{1}{4}\\\\=\frac{3}{8}-\frac{2}{8}\\\\=\frac{3-2}{8}}\\\\=\frac{1}{8}\\\\ =.125$