Question

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Answer 1

Respuesta:

$-\sqrt[5]{16}.\sqrt[5]{2} = -\sqrt[5]{16.2}=-\sqrt[5]{32} = -2\\+27^{\frac{1}{3} }=+\sqrt[3]{27} = 3\\-(\frac{1}{2} )^{-1} = -2$

  -2          +3          -2

8------> 6 ------> 9 ------> 7