Question

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tema : algebra

Answer 1

$\sqrt{( { \frac{1}{6} })^{ - 2} +({\frac{1}{8} })^{ - 2} } \\ = \sqrt{( { \frac{6}{1} })^{ 2} +({\frac{8}{1} })^{ 2} } \\ = \sqrt{36 + 64} \\ = \sqrt{100} \\ = 10$

Por tanto sería la B