AYUDAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
Respuestas a la pregunta
Respuesta:
ESSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPEEEEEEEEEEEEEEEEEEEEEEEEEEEEEERRRRRRRRRRRRRRRAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ YYYYYYYYYAAAAAAAAAAAAAAAAAAAA TTTTTTTTTTTTTTTTEEEEEEEEEEEEEEE AAAAAAAAAAAAAAAAYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDOOOOOOOOOOOOOOOOOOO
Explicación paso a paso:
Respuesta:
am4(b) .... (1)
m31(a) .....(2)
ccc(7) .....(3)
2baa(c) ....(4)
Por propiedad, se sabe que la base siempre es mayor que los números del numeral.
De (2):
3<a
De (1):
a<b
De (4):
b<c
De (3):
c<7
Por lo tanto:
3<a<b<c<7
a=4; b=5 c=6
Entonces quedaría:
am4(b) =4m4(5)
m31(a) = m31(4)
ccc(7) = 666(7)
2baa(c) = 2544(6)
Si asumimos que cada letra es un número diferente; m=2
Entonces:
4m4(5) = 424(5) = 129
m31(4) = 231(4) = 45
666(7) = 666(7) = 342
2544(6) = 2544(6) = 640
Por lo tanto el total de electrodomesticos es:
129+45+342+640 = 1156
Explicación paso a paso: